Test in Trigonometry 

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Master Trigonometry: Test Your Skills

Welcome to the Master Trigonometry Quiz, where you can put your trigonometric knowledge to the test! This quiz consists of a series of challenging questions designed to assess your understanding of trigonometry concepts and formulas.

Join today and find out how well you know trigonometry!

  • 20 carefully curated questions
  • Multiple-choice answers
  • Score your knowledge instantly!
21 Questions5 MinutesCreated by CalculatingStar487
Roll Number
The value of cos 0°. cos 1°. cos 2°. cos 3°… cos 89° cos 90° is=
1
-1
0
1/√2
If x tan 45° sin 30° = cos 30° tan 30°, then x is equal to=
ˆš3
½
1/√2
1
If A and (2A – 45°) are acute angles such that sin A = cos (2A – 45°), then tan A is equal to=
0
1/√3
1
ˆš3
5 tan² A – 5 sec² A + 1 is equal to=
6
-5
1
-4
If cos 9A = sin A and 9A < 90°, then the value of tan 5A is=
0
1
1/√3
ˆš3
The value of the expression [cosec (75° + θ) – sec (15° – θ) – tan (55° + θ) + cot (35° – θ)=
-1
0
1
3/2
A rhombus has side 20 cm and has 2 angles 60° each, then the length of the diagonals (in cm) is=
20√3 , 20
15√3 , 15
20 , 10
12√3 , 12
Given that sinα = √3/2 and cosβ =0, then the value of β - α is=
90°
60°
30°
0°
If cos (A + B ) = 0 then sin (A – B) is reduced to=
Cos A
Cos 2B
Sin A
Sin 2B
In ΔOPQ, right-angled at P, OP = 7 cm and OQ – PQ = 1 cm, then the values of sin Q.=
7/25
24/25
1
7/24
(sec A + tan A) (1 – sin A) =
Sec A
Sin A
Cosec A
Cos A
The value of tan 48° tan 23° tan 42° tan 67° is=
1
9
8
0
If ΔABC is right angled at B, then the value of cos(A + C) is=
0
1
1/2
ˆš3/2
In a right triangle ABC, right-angled at B, if tan A = 1, then the value of 2 sin A cos A =
0
1
½
2
If tanθ = √2-1 , then the value of tanθ / (1+ tan2θ) is=
1/√2
ˆš2
¼
ˆš2/4
Sin 2A = 2 sin A cosA is true when A =
0°
30°
45°
60°
If 3tanA = 4, then the value of 3sinA+ 2cosA /3sinA -2cosA is=
1
725
3
2425
The value of 2cos² 60º + 3sin² 45º - 3sin² 30º + 2cos² 90º is=
1
5
5/4
4/5
Sinθ / (1+ cosθ) =
(1+ cosθ) / sinθ
(1- cosθ) / cosθ
(1- cosθ) / sinθ
(1- sinθ) / cosθ
(1 - cos²A)cosec² A =
1
2
½
0
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