Elementi I jedinjenja IVA grupe PSE

Generate an educational illustration showing the chemical structures and reactions of Group IVA compounds, including Sn(OH)2 and Pb(OH)2, with a colorful and engaging background.

Explore Group IVA Compounds Quiz

Test your knowledge of Group IVA compounds and their chemical reactions through our engaging quiz. Dive into the properties, reactions, and characteristics of compounds like Sn(OH)2 and Pb(OH)2.

In this quiz, you will:

  • Answer questions about electrolytes and their properties.
  • Identify different types of chemical reactions.
  • Convert percentages and understand color changes in solutions.
11 Questions3 MinutesCreated by ChemicalFact247
Ime, prezime I broj indeksa
Elektrolit Sn(OH)2 ima:
Kiseli karakter
Bazni karakter
Amfoterni karakter
Neutralni karakter

Sn(OH)2↓+ 2NaOH → Na2[Sn(OH)4]

Prikazana jednaĝina je:

Reakcija rastvaranja
Reakcija oksido-redukcije
Reakcija taloženja
Reakcija kompleksiranja
3SnCl2 + 2K2CrO4 +16HCl → 3SnCl4 + 2CrCl3 + 8H2O + KCl

Prikazana jednaĝina je:

Reakcija oksido-redukcije
Reakcija neutralizacije
Reakcija taloženja
Reakcija rastvaranja
Rastvor SnCl2 je:
Žut
Zelen
Bezbojan
Beo

U reakciji 3SnCl2 + 2K2CrO4 +16HCl → 3SnCl4 + 2CrCl3 + 8H2O + KCl

K2CrO4 je:

Oksidaciono sredstvo
Redukciono sredstvo
Elektrolit Pb(OH)2 ima:
Kiseli karakter
Bazni karakter
Amfoterni karakter
Neutralni karakter

Pb(OH)2↓+ 2NaOH → Na2[Pb(OH)4]

Prikazana jednaĝina je:

Rakcija rastvaranja
Reakcija oksido-redukciona
Reakcija taloženja
Reakcija kompleksiranja
Izraziti 0,09% u ppb

Prilikom oksido-redukcione reakcije:

3SnCl2 + 2K2CrO4 +16HCl → 3SnCl4 + 2CrCl3 + 8H2O + KCl

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