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Quizzes > Mathematics

Math 1 EOC Practice Test and Review Packet Quiz

Quick, free quiz for your EOC Math 1 review. Instant results.

Editorial: Review CompletedCreated By: Brittany Latiffiny CooperUpdated Aug 26, 2025
Difficulty: Moderate
Grade: Grade 9
Study OutcomesCheat Sheet
Colorful paper art promoting a Math 1 EOC Mastery trivia quiz for high school students.

This quiz helps you work through the Math 1 EOC review packet with a short Math 1 EOC practice test, so you can spot weak areas and focus your study. When you finish, explore more practice with our geometry EOC practice test or check algebra skills in the algebra 1 practice test.

Solve for x: 2x + 5 = 13.
x = 5
x = 3
x = 4
x = 6
Subtracting 5 from both sides gives 2x = 8, and dividing by 2 leads to x = 4. This problem demonstrates basic algebraic manipulation.
What is the slope of the line passing through the points (1, 2) and (3, 6)?
3
1
4
2
Using the slope formula (y2 - y1)/(x2 - x1), we have (6 - 2)/(3 - 1) = 4/2, which simplifies to 2. This is a basic application of the slope formula.
Evaluate 3².
3
6
12
9
Raising 3 to the power of 2 means multiplying 3 by itself, which results in 9. This reinforces the fundamental concept of exponents.
Which point lies on the line y = 2x + 1 when x = 2?
(2, 4)
(2, 3)
(2, 5)
(2, 6)
Substitute x = 2 into the equation: y = 2(2) + 1 = 5. Thus, the point on the line is (2, 5). This exercise practices evaluating linear functions.
Which expression is equivalent to 4(x + 2)?
4x + 2
4x + 16
x + 8
4x + 8
Applying the distributive property, 4(x + 2) expands to 4x + 8. This reinforces the concept of distribution in algebra.
Solve for x: 3(x - 2) = 2x + 4.
8
14
12
10
Expanding the left side gives 3x - 6, so the equation becomes 3x - 6 = 2x + 4. Subtracting 2x from both sides and then adding 6 leads to the solution x = 10.
Simplify the expression: 2a(3a + 4) - 3a².
6a² - 8a
3a² + 8a
3a² - 8a
6a² + 8a
First, distribute 2a into (3a + 4) to get 6a² + 8a, and then subtract 3a². Combining like terms results in 3a² + 8a, which is the simplified form.
Find x if 5/x = 2/3.
10/3
7/2
15/2
5/2
Cross multiplying 5/x = 2/3 gives 5-3 = 2x, which simplifies to 15 = 2x. Dividing both sides by 2 yields x = 15/2.
Factor the quadratic expression: x² - 5x + 6.
(x - 3)(x + 2)
(x - 1)(x - 6)
(x - 2)(x - 3)
(x + 2)(x + 3)
The numbers -2 and -3 multiply to give 6 and add to give -5. Hence, the quadratic factors as (x - 2)(x - 3), which is the correct factorization.
Determine the x-intercept of the line given by y = 3x - 9.
(-3, 0)
(9, 0)
(3, 0)
(0, -9)
To find the x-intercept, set y = 0. This yields 0 = 3x - 9, and solving for x gives x = 3. Therefore, the x-intercept is (3, 0).
Simplify the expression: (2x²y) / (4xy²).
2x/y
x/(2y)
2/(xy)
x²/(2y²)
Cancel the common factors: 2/4 simplifies to 1/2, x²/x becomes x, and y/y² simplifies to 1/y. Thus, the expression reduces to x/(2y).
Solve the inequality: 2x - 3 > 5.
x ≥ 5
x > 4
x ≥ 4
x > 3
First add 3 to both sides to get 2x > 8, then divide by 2 to obtain x > 4. This inequality signifies that x must be strictly greater than 4.
Find the solution to the equation: x/2 = 3 - (x/4).
3
2
4
6
Multiplying the entire equation by 4 to eliminate fractions gives 2x = 12 - x. Solving for x yields 3x = 12, so x = 4.
Evaluate the expression: √16 + √9.
7
6
9
8
The square root of 16 is 4 and the square root of 9 is 3. Their sum, 4 + 3, equals 7.
If f(x) = 2x + 3, what is the value of f(4)?
10
11
8
12
Plug x = 4 into the function f(x) = 2x + 3. This gives f(4) = 2(4) + 3 = 11. It is a straightforward evaluation of a linear function.
Find the positive solution of the quadratic equation: x² - 4x - 5 = 0.
-1
5
4
-5
Factoring the equation gives (x - 5)(x + 1) = 0, so x = 5 or x = -1. Since only the positive solution is requested, x = 5 is correct.
What is the distance between the points (2, -3) and (-1, 1)?
3
5
4
6
Using the distance formula, calculate √[((-1) - 2)² + (1 - (-3))²] = √[(-3)² + (4)²] = √(9 + 16) = √25, which is 5. This problem tests understanding of coordinate geometry.
If 3^(2x) = 81, what is the value of x?
3
2
1
4
Notice that 81 can be expressed as 3^4. Equating the exponents in 3^(2x) = 3^4 gives 2x = 4, so x = 2. This applies the property of exponents.
The area of a triangle is given by (1/2)bh. If the area is 24 and the base is 6, what is the height?
4
6
8
10
Substitute the known values into the formula: (1/2)(6)(h) = 24 leads to 3h = 24. Solving for h yields h = 8. This problem involves solving a simple equation.
Solve the system of equations: 2x + y = 10 and x - y = 1. What is the ordered pair (x, y)?
(4, 3)
(11/3, 8/3)
(8/3, 11/3)
(3, 4)
Solve the second equation to express x as y + 1 and substitute into the first equation. This leads to x = 11/3 and y = 8/3, which satisfy both equations in the system.
0
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Study Outcomes

  1. Analyze key algebraic expressions and equations to identify problem-solving paths.
  2. Apply techniques to simplify and solve linear and quadratic equations.
  3. Interpret graphs and functions to understand relationships between variables.
  4. Evaluate geometric concepts and their applications in polynomial contexts.
  5. Identify areas of misunderstanding to target further practice and improvement.
  6. Assess overall mathematical proficiency to build confidence for tests and exams.

EOC Review Packet: Math 1 Answer Key PDF Cheat Sheet

  1. Master the Slope-Intercept Form - Get comfortable with the classic y = mx + b equation, where m tells you how steep your line is and b shows where it crosses the y‑axis. Being a graphing superstar means you can sketch any line in seconds and interpret real‑world trends like a pro.
  2. Apply the Quadratic Formula - Whenever you see ax² + bx + c = 0, whip out x = ( - b ± √(b² - 4ac))❄(2a) to find your roots in no time. It's your secret weapon for tackling those tricky parabolas and will save your grade when factoring fails.
  3. Understand the Distance Formula - From (x₝, y₝) to (x₂, y₂), d = √[(x₂ - x₝)² + (y₂ - y₝)²] measures exactly how far apart two points are. Perfect for coordinate geometry quests, this formula turns a messy distance problem into a quick computation.
  4. Utilize the Midpoint Formula - Need the halfway point between (x₝, y₝) and (x₂, y₂)? Just calculate ((x₝ + x₂)❄2, (y₝ + y₂)❄2) and voilà - you've split any segment evenly. Critical for bisecting lines and designing perfect geometry constructions.
  5. Remember the Pythagorean Theorem - In right triangles, a² + b² = c² links your two legs to the hypotenuse. It's the OG geometry formula and pops up everywhere from architecture to navigation - never face a missing side length unprepared.
  6. Grasp the Concept of Slope - Slope m = (y₂ - y₝)❄(x₂ - x₝) tells you how tilt-y your line is and which way it leans. Mastering slope means you can predict trends, compare rates of change, and dominate linear modeling.
  7. Learn the Standard Form of a Line - Ax + By = C might look old school, but it's perfect for quick integer solutions and conversions between forms. Flip back and forth to unlock new strategies for solving intercepts and system problems.
  8. Explore Exponential Functions - Equations like y = a · bˣ model everything from viral growth to radioactive decay. Knowing how to tweak a and b gives you the power to forecast populations, investments, or half‑life phenomena.
  9. Understand Systems of Equations - Substitution, elimination or graphing - you pick the method to find where two (or more) lines collide. Practice these techniques to solve real‑life puzzles like budget planning and motion problems.
  10. Practice with EOC Review Sheets - Power up your prep with all‑in‑one sheets that bundle formulas, example problems, and practice tests. They're your go‑to tool for pinpointing weak spots and boosting confidence before test day.
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