"CHEM JUST" 107 Mid-Term Exam ( Created By : Omar Kofahi )
CHEM JUST 107 Mid-Term Exam
Welcome to the CHEM JUST 107 Mid-Term Exam! This quiz is designed to assess your understanding of fundamental chemistry concepts, practical applications, and problem-solving skills.
Prepare yourself with a variety of questions that cover key topics such as:
- Chemical reactions
- Quantitative analysis
- Laboratory techniques
- Properties of substances
- Understanding of gaseous reactions
Which of the following glass wares could be used for heating a mixture :
Buchner funnel
Test tube
Evaporating dish
Graduated cylinde
7.896g of Ca3(PO4)2 (MM=310) was reacted with excess HCL according to Ca3(PO4)2 + 2HCL ----------> Ca(H2PO4)2 + 2CaCl2 If 3.245g of Ca(H2PO4)2 (MM=234) were produced the the percent yield is :
35.35
36.5
66.5
54.45
Degree of agreement of measured values with the true values is defined as
Precision
Accuracy
Vinegar
Non of above
In which of the following weights , the precission of balance is +- 0.01
6.2g
8.235g
5.12g
101g
Calculate the freezing point of a solution made by dissolving 30 g of ethylene glycol (MM=62g/mol) in 70g of water (Tf = 0Cْ , Kf = 1.86 c/m) :
-24.5 Cْ
-12.9 Cْ
-12.5 Cْ
25.4 Cْ
H2 gas could be evolved through the addition of :
Strong acid to table salt
Hot water to drain opener
Strong base to fertilizer
Non of above
The density of Oil was calculated to be 0.875 g/cm^3 at 25 Cْ the mass (mg) of 6.3 dm^3 of Oil sample is (use correct S.F) :
5.5 × 10^-6
5.52 × 10^-6
5.5 × 10^6
Non of above
How many moles of NO2(g) could be produced through the reaction of 0.20 moles of NO with 0.30 moles O2 according to the following equation NO(g) + 1/2 O2(g) ----------> NO2 (g)
0.30
0.20
0.40
0.60
Which of the following is Bathroom cleaner :
NaCl
HCO3
HCl
NaHCO3
The active chemical ingredient in Glass cleaner is :
NH3
HCl
NaCl
HCO3
A mixture of BaCl2.2H2O and Na3PO4.10H2O weighting 8.77g was dissolving in distilled water and heated 2.33g of Ba3(PO4)2 was precipitated according to 2PO4^-3 + 3Ba^+2 -------> Ba3(PO4)2 .......... If PO4^-3 is th limiting reactant then the mass percent of the excess reactant in the mixture is :
60.9
56.5
58.5
75.6
66.5
66.4
When 2.0g of aluminum (At Mass = 27 g/mol) is reacted completely with excess HCL , it given 4..6g of AlCl3 (MM = 133.5g/mol) The percent yield of this reaction is : 2Al + 6HCL -----> 2AlCl3 + H2
56
74
47
58
The limiting reactant is :
The reactant that has the smallest number (of moles)
The reactant that has the largest number (of moles)
Non of above
The percent that has the smallest mass
Solid NaCl can be separated from solid NH4Cl by dissolving the mixture in water then heating the mixture
True
False
A mixture containing 0.5g of SiO4 , 20% (wt/wt) , NaCl and unknown amount of NH4Cl, when the mixture was heated , it's mass was decreased to 1.0g , The mass of NH4Cl in the mixture is :
1.5g
2.5g
3.5g
4.5g
When concentrated H2SO4 was added to solid unknown ,colorless and odorless bubbles was evolved the unknown could be
NaCl
Na2SO4
NaI
Na2CO3
X + 2HCl ----> Y + 2HNO3 ,,,,,,,,,,,,,,,,, Y + 2NH3 -------> Hg + Z + NH4Cl In above equation : X and Z respectively are :
Hg2Cl2 , HgNH2Cl
Hg2(NO3)2 , Hg2Cl2
Hg2Cl2 , Hg2(NO3)2
Hg2(NO3)2 , HgNH2Cl
Which one of the following numbers contains 5 S.F ?
0.0020004
0.00001
0.0102
Non of above
How many grams of glycerol (M.M = 92g/mol) should be added to 200.0g water , if the freezing point of solution decreased by 30 ْC (for Kf = 1.86 Cْ/m)
19.8
29.7
8.6
39.6
296.7
297
As the amount of solute added to solution decrease
Freezing point will decrease
Boiling point will decrease
Vaper pressure will decrease
Osmotic pressure will increase
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