Challenge Yourself #CHAPTER2

If G is a Prime order group, then G has
No Proper Subgroup
No Improper Subgroup
Two Improper Subgroups
Number of proper Subgroups of Z6 is
3
4
1
2
Let G be a group order 6, and H be a subgroup of G such that 1 < |H| < 6. Which one of the following options is correct?
G is always cyclic, but H may not be cyclic.
G may not be cyclic, but H is always cyclic.
Both G and H are always cyclic.
Both G and H may not be cyclic.
If (G, ⋅) is a group such that (ab)-1 = a-1 b-1, ∀ a, b ∈ G, then G is a/an
Commutative semi group
Abelian group
Non-Abelian group
The number of generators of the cyclic group G of order 8 is
1
2
3
4
Any group of order 3 is
Cyclic and Abelian
Cyclic but not Abelian
Infinite cyclic group
A subgroup has the properties of ________.
Closure, associative
Commutative, associative, closure
Inverse, identity, associative
Closure, associative, Identity, Inverse
A trivial subgroup consists of ___________.
Identity element
Coset
Inverse element
Ring
A normal subgroup is ____________.
A subgroup under multiplication by the elements of the group.
An invariant under closure by the elements of that group.
A monoid with same number of elements of the original group.
an invariant equipped with conjugation by the elements of original group.
If a * b = a such that a ∗ (b ∗ c) = a ∗ b = a and (a * b) * c = a * b = a then ________.
* is associative
* is commutative
* is closure
* is abelian
The set of rational numbers form an abelian group under _________.
Association
Closure
Multiplication
Addition
If x * y = x + y + xy then (G, *) is _____________.
Abelian group
Commutative semigroup
Cyclic group
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